SOLUTION: I will form a 6 letter code word using only the first 12 letters of the alphabet and allow repeated letters. If I select a code word at random find the probability that the code wo

Algebra.Com
Question 875360: I will form a 6 letter code word using only the first 12 letters of the alphabet and allow repeated letters. If I select a code word at random find the probability that the code word has no vowels

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
The first 12 letters of the alphabet are

ABCDEFGHIJKL

Of those, 3 are vowels and 9 are consonants.

So the probability that each one is a consonant is  or 

So the probability that the 1st and the 2nd and the 3rd are

consonants is  =  = 

Edwin

RELATED QUESTIONS

4. How many 3-letter code words are possible using the first 8 letters of the alphabet if (answered by ramkikk66)
How many 3-letter code words are possible using the first 8 letters of the alphabet if... (answered by scott8148)
How many 3-letter code words are possible using the first 7 letters of the alphabet if... (answered by Alan3354)
How many 2-letter code words can be formed from the first 6 letters of the alphabet if... (answered by Fombitz)
How many 4-letter code words are possible using any of the letters of the alphabet if... (answered by TimothyLamb)
How many different 4-letter radio call letters can be made using the 26 capital letters... (answered by oberobic,josmiceli)
How many seven letter code words can be formed using a standard 26 letter alphabet if... (answered by VFBundy,Edwin McCravy)
How many 4-letter code words are possible using the first 8 letters of the alphabet when... (answered by sudhanshu_kmr)
if 4-letter "words" are formed using the letters A, B, C,D,E, F,G, how many such words... (answered by sudhanshu_kmr,edjones)