SOLUTION: Prove a permutation of 4 letters does not have 40 distinct elements but a permutation of 5 letters has 50 distinct elements.

SOLUTION: Prove a permutation of 4 letters does not have 40 distinct elements but a permutation of 5 letters has 50 distinct elements.

Algebra.Com

Question 862687: Prove a permutation of 4 letters does not have 40 distinct elements but a permutation of 5 letters has 50 distinct elements.
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
A permutation of five letters or objects does not have 50 distinct "elements." I think what you meant to say is that "the set of permutations of 5 letters has 50 distinct elements" which is true since 5! = 120 >= 50, while 4! < 40.
RELATED QUESTIONS
I do not understand inverse permutations. For example, the permutation of (1 2 3 4 5),... (answered by jim_thompson5910)

Find the number of permutation of the letters milk (answered by ikleyn)

What is the total number of permutation of... (answered by ikleyn)

Use either the fundamental counting principle or the permutation formulas (or both) to... (answered by stanbon)

Arrange the letters O,R,A,N,G, and E in a row. find the number of... (answered by ikleyn)

A set has 10 elements. How many i5f its 1024 distinct subsets have 3 elements... (answered by stanbon)

Find the number of ways to arrange the letters in the following words: a. scramble b.... (answered by ewatrrr)

Of the following statements which one is not true? A. A combination is a selection of (answered by ikleyn)

A class has 15 girls and 19 boys. A committee is formed with two girls and two boys, each (answered by jim_thompson5910)