SOLUTION: A menu offers 7 different salads and 5 different entrees. How many ways are there to choose 3 salads and 2 entrees?

Question 857659: A menu offers 7 different salads and 5 different entrees. How many ways are there to choose 3 salads and 2 entrees?
Answer by ben720(159) (Show Source): You can put this solution on YOUR website!

The total number of permutations is the possible salads times the possible entrees, because for each salad combo, there are that many entrees. (Same as how with all 100 numbers, there are ten ones digits for each tens digit, as in 61 and 71, etc.)

SALADS * ENTREES = PERMUTATIONS (P)

The salad permutations are 7*6*5 because for the first salad there are seven choices, for the next (as you can't choose the same twice, presumably) there are six, and for the next there are 5.

7*6*5*ENTREES = P

The Entree permutations are 5*4 because there are all 5 choices for the first, then only 4 for the next.

7*6*5 * 5*4 = P

Simplify by multiplication

4200 = P

There are 4200 permutations.
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