Hi,
Note: shortlisted 2/3 of the time
'short listed' ... more family than friends in the group of 3
A. 2C2*5C1 are the 5 ways there are more family than friends:
P(shortlisted) = 2C2*5C1/7C3 = 5/35 = 1/7
P(shortlisted 2/3 of the time ) = (2/3)(1/7) = 2/21 = .0952
b. P =