SOLUTION: how many permutations can be obtained by letter COURAGE if: (a)constants occupy the even places, (b)A and E occupy the ends, (c)C and E come together?

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Question 849405: how many permutations can be obtained by letter COURAGE if:
(a)constants occupy the even places,
(b)A and E occupy the ends,
(c)C and E come together?

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
COURAGE has 3 consonants and 4 vowels

how many permutations can be obtained by letter COURAGE if:
(a)constants occupy the even places,
V C V C V C V

Choose the 2nd letter as a consonant 3 ways.
Choose the 4th letter as a consonant 2 ways.
Choose the 2nd letter as a consonant 1 way.
Choose the 1st letter as a vowel 4 ways.
Choose the 3rd letter as a vowel 3 ways.
Choose the 5th letter as a vowel 2 ways.
Choose the 7th letter as a vowel 1 way.

Answer 3×2×1×4×3×2×1 = 3!4! = 6×24 = 146 ways
(b)A and E occupy the ends,
5! ways for A _ _ _ _ _ E and 5! for E _ _ _ _ _ A

Answer:  2×5! = 2×120 = 240 ways
(c)C and E come together?
That's the number of permutations of the 6 things {CE,O,U,R,A,G)
plus the number of permutations of the 6 things {EC,O,U,R,A,G)

That's 2×6! = 2×720 = 1440 ways.

Edwin

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