SOLUTION: A committee of four children is chosen from eight children. The two oldest children cannot both be chosen. Find the number of ways the committee may be chosen.

Algebra.Com
Question 842104: A committee of four children is chosen from eight children. The two oldest children cannot both be chosen. Find the number of ways the committee may be chosen.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
A committee of four children is chosen from eight children.
The two oldest children cannot both be chosen.
Find the number of ways the committee may be chosen.

RELATED QUESTIONS

A committee of five is to be selected from a group of 12 children. The two youngest... (answered by ewatrrr)
Four persons are to be chosen at random from a group containing 3 men 2 woman and 4... (answered by Edwin McCravy)
In how many ways can a party of 6 children be chosen from a group of 10 children if... (answered by MusabShakeel,ikleyn)
a group of five children has to be chosen from a form of eight boys and twelve girls.in... (answered by Edwin McCravy)
Given a family with four children, find the probability of the event. The oldest two are (answered by ikleyn,greenestamps)
Q15 In how many ways can we distribute seven apple and six oranges among 4 children so... (answered by lynnlo)
A committee of 8 people is to be chosen from 7 men and 5 women.find the number of... (answered by Boreal)
The ages of three family children can be expressed as consecutive integers. The square... (answered by josgarithmetic)
The ages of three family children can be expressed as consecutive integers. The square... (answered by josgarithmetic)