A coin is tossed 9 times. What is the
probability that the coin will land heads
at least 7 times?
This is a binomial probability. You can
find it directly from a binomial
table, a TI-83 calculator, or entirely
from the formula.
Using the formula:
gives the probability that in n trials
there will be exactly x successes
where
p = the probability of one success in
one trial and q = 1-p = the probability
of one failure in one trial.
In the case of a coin, p = 1/2 and q = 1 - 1/2 = 1/2
P(coin landing heads at least 7 times out of 9 tosses) =
P(coin landing exactly 7 times out of 9) +
P(coin landing exactly 8 times out of 9) +
P(coin landing exactly 9 times out of 9) =
=
=
Factor out
=
which gives the desired probability.
To calculate this we need:
Therefore the desired probability =
----------------------------------------------
If you use a TI-83 or TI-84 calculator, type in
1 - binomcdf(9,1/2,6)
then press ENTER and you get .08984375
To get binomcdf( , press 2nd, then VARS, then
scroll down to binomcdf( , then press ENTER.
Edwin