SOLUTION: There are seven finalists for two scholarships. Four of them are girls and three of them are boys. In how many ways can the scholarships be awarded to one boy and one girl?

SOLUTION: There are seven finalists for two scholarships. Four of them are girls and three of them are boys. In how many ways can the scholarships be awarded to one boy and one girl?

Algebra.Com

Question 748167: There are seven finalists for two scholarships. Four of them are girls and three of them are boys. In how many ways can the scholarships be awarded to one boy and one girl?

Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
This is a counting problem perfect for the counting principle.
4 ways to choose a girl
3 ways to choose a boy
ways to choose a girl and a boy: (4)(3)=12
RELATED QUESTIONS
There are seven finalists for two scholarships. Four of them are girls and three of them... (answered by ewatrrr)

There are nine finalists in a certain competition.In how many ways can the judges choose... (answered by stanbon)

Two of seven finalists will be selected and awarded $10,000 scholarships. In how many... (answered by solver91311)

In class there are 20 students 75% of them are girls how many students are boys? (answered by ewatrrr)

There are five boys and seven girls. In how many ways can you arrange all kids in a row... (answered by sudhanshu_kmr)

In a classroom there are seven girls and five boys. A group of 3 girls and two boys are... (answered by stanbon)

There are four girls and six boys in a class. They are arranged randomly at 10 seats. (answered by ikleyn)

There are four girls and six boys in a class. They are arranged randomly at 10 seats. i. (answered by ikleyn)

how do you do this?There are 30 students in a class, and three-fifths of them are girls.... (answered by Alan3354)