SOLUTION: This is a question I had trouble with:
From a group of 5 boys and 4 girls, a committee of 4 must be selected. The committee must have at least one boy and at least one girl.
Algebra.Com
Question 732606: This is a question I had trouble with:
From a group of 5 boys and 4 girls, a committee of 4 must be selected. The committee must have at least one boy and at least one girl. How many ways can this be done?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
There are 5 ways to choose the required 1 boy. Then, for each of those 5 ways, there are 4 ways to choose the required 1 girl. Then for each of those 20 ways, there remain 7 people, so 7 ways to choose the third committee member, and finally 6 ways to choose the fourth committee member. Altogether, 5 times 4 times 7 times 6. You can do your own arithmetic.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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