SOLUTION: this term there are eight candidates for three student senate seats, how many different ways can the seats be chosen?

Question 70126: this term there are eight candidates for three student senate seats, how many different ways can the seats be chosen?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
this term there are eight candidates for three student senate seats, how many different ways can the seats be chosen?
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You want "groups" rather than "order".
So you want combinations rather than permutations.
8C3=[8*7*6]/[1*2*3]=56 sets of three
Cheers,
Stan H.
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