# SOLUTION: Given the digits 3,9,5,6& 2, howmany different 5 digit numbers reater than 41,000(using each digit once) can form?

Algebra ->  Algebra  -> Permutations -> SOLUTION: Given the digits 3,9,5,6& 2, howmany different 5 digit numbers reater than 41,000(using each digit once) can form?      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Combinatorics and Permutations Solvers Lessons Answers archive Quiz In Depth

 Question 69055: Given the digits 3,9,5,6& 2, howmany different 5 digit numbers reater than 41,000(using each digit once) can form?Answer by josmiceli(9668)   (Show Source): You can put this solution on YOUR website!The 1st digit can't be 2 or 3 So, it has to be 5,6,or 9, or 3 choices One digit is used up and there are 4 choices for the next digit There are 3 choices for the next There are 2 choices for the next And 1 choice for the last multiply all the choices together to get all the possible combination possible numbers greater than 41,000 using each digit only once