SOLUTION: If x + y = 4 what is the perimeter of a square with side length 2x^2 + 4xy + 2y^2?

SOLUTION: If x + y = 4 what is the perimeter of a square with side length 2x^2 + 4xy + 2y^2?

Algebra.Com

Question 687086: If x + y = 4
what is the perimeter of a square with side length 2x^2 + 4xy + 2y^2?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

2x^2 + 4xy + 2y^2

2(x^2 + 2xy + y^2)

2(x + y)^2

2(4)^2

2(16)

32

So if x+y = 4, then 2x^2 + 4xy + 2y^2 = 32

So the side length is 32 units.

The perimeter is then 32*4 = 128 units
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