SOLUTION: 3 girls & 4 boys are to be seated in a row containing 7 chairs. If the chairs at both ends of the row must be occupied by girls, in howmany different ways can the children be seate

SOLUTION: 3 girls & 4 boys are to be seated in a row containing 7 chairs. If the chairs at both ends of the row must be occupied by girls, in howmany different ways can the children be seate

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Question 68461: 3 girls & 4 boys are to be seated in a row containing 7 chairs. If the chairs at both ends of the row must be occupied by girls, in howmany different ways can the children be seated?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
3G & 4B LESS 2G THEN WE HAVE 1G & 4B CAN BE ARRAINGED IN
5*4*3*2*1 DIFFERENT WAYS OR
5*4*3*2*1=120 WAYS TO SEAT THE REMAINING 5 CHILDREN
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