SOLUTION: we want to form a 4 letter password using letters from A,B,C,D,E,F without repetition, what is the probability that the first letter of the password is A and the last letter is F??

Question 681934: we want to form a 4 letter password using letters from A,B,C,D,E,F without repetition, what is the probability that the first letter of the password is A and the last letter is F??
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
4 letter password using letters from A,B,C,D,E,F
By assuming that the first letter is "A", and the last letter is �F",

Therefore, one has to find two more letters from the remaining 4 letters.
Of the 4 letters, there are 1 B, 1 C, 1 D, and 1 E .
The second and third positions can have two different letters.
When the two letters are different. One has to choose two different letters from the 4 available different choices. This can be done in 4 * 3=12 ways.

Total number of possibilities is 12.
1. A,B,C,F
2. A,C,B,F
3. A,B,D,F
4. A,D,B,F
5. A,C,D,F
6. A,D,C,F
7. A,C,E,F
8. A,E,C,F
9. A,D,E,F
10. A,E,D,F
11. A,B,E,F
12. A,E,B,F
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