# SOLUTION: A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf? My answer was 28. I found this by using the follo

Algebra ->  Algebra  -> Permutations -> SOLUTION: A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf? My answer was 28. I found this by using the follo      Log On

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 Algebra: Combinatorics and Permutations Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Permutations Question 612215: A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf? My answer was 28. I found this by using the following combination: (8 nCr 6) = 28 I was marked wrong, what is the correct way to do this problem and how can i avoid this mistake in the future?Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf? --- Ans: 8P6 = 8!/(8-6)! = 8*7*6*5*4*3 = 20160 ============================================ Cheers, Stan H. ===============