SOLUTION: A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf? My answer was 28. I found this by using the follo

Algebra ->  Algebra  -> Permutations -> SOLUTION: A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf? My answer was 28. I found this by using the follo      Log On

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Question 612215: A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf?
My answer was 28. I found this by using the following combination:
(8 nCr 6) = 28
I was marked wrong, what is the correct way to do this problem and how can i avoid this mistake in the future?
Answer by stanbon(57282) About Me  (Show Source):
You can put this solution on YOUR website!
A bookself has space for 6 books. If 8 different books are available, how many different arrangements can be made on the shelf?
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Ans: 8P6 = 8!/(8-6)! = 8*7*6*5*4*3 = 20160
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Cheers,
Stan H.
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