SOLUTION: So there are three seats, each one can either be filled by a boy or a girl. How many different combinations are there with repetition? I know that there are 4: BBB BBG BGG

Question 607029: So there are three seats, each one can either be filled by a boy or a girl. How many different combinations are there with repetition?
I know that there are 4:
BBB
BBG
BGG
GGG
However, I don't know the equation to find this... Could you help? Much obliged!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
There are 2^3 = 8 ways to fill 3 seats with either a boy or a girl. Since order doesn't matter (and something like BBG = BGB and BBG = GBB), we're over-counting and need to divide by 2! = 2*1 = 2 to get

8/2 = 4

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