SOLUTION: Find the number of ways in which each commitee can be selected.
-3 people from a group of 5
Algebra.Com
Question 600714: Find the number of ways in which each commitee can be selected.
-3 people from a group of 5
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
C(n,r) = (n!)/(r!(n-r)!)
C(5,3) = (5!)/(3!*(5-3)!)
C(5,3) = (5!)/(3!*2!)
C(5,3) = (5*4*3!)/(3!*2!)
C(5,3) = (5*4)/(2!)
C(5,3) = (5*4)/(2*1)
C(5,3) = (20)/(2)
C(5,3) = 10
So there are 10 ways (assuming order doesn't matter)
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