SOLUTION: How many committees of two or more can be selected from 10 people?
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Question 583347: How many committees of two or more can be selected from 10 people?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The number of ways is 10C2 + 10C3 + ... + 10C10. If you know that 10C0 + 10C1 + 10C2 + ... + 10C10 = 2^10 = 1024, we can take this and subtract off 10C0 and 10C1, leaving 1024 - 1 - 10 = 1013.
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