SOLUTION: How many numbers divisible by 5 and lying between 5000 and 9000 can be formed from the digits 5, 6, 7, 8 and 9?

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A number is divisible by 5 if it ends in 5 or 0. Since zero is not an option, it must end in 5.
Also, we need to note that using the digits given, if we start with a 9, we will go over 9000 (because, again, 0 is not an option)
Now, assuming we can use each digit more than once,
for the first digit we have 4 options, for the next, 5 options, 5 options again (and the last digit just had one option)
So we get that there are 100 possibilities.