Question 54142: My answer to the problem stated below 1/10 = 0.1 Am I correct?
Problem:
A couple plans to have 4 children.Assuming the probability of obtaining each sex is 50% (1 in 2), find the probability of the couple getting 4 boys.
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! There's a couple of ways of doing this:
The multiplication rule:
Multiply the probabilty of having a boy and a boy and a boy and a boy.
You can also raise the probability to the power of 4.
If you aren't to that point in your book, P=(#of ways to have 4 boys)/(# of ways to have children)
There is 1 way to have 0 boys: (GGGG)
There are 4 ways to have 1 boys: (BGGG),(GBGG),(GGBG),(GGGB)
There are 6 ways to have 2 boys: (BBGG),(GBBG),(GGBB),(BGBG),(GBGB),(BGGB)
There are 4 ways to have 3 boys: (BBBG),(BBGB),(BGBB),(GBBB)
There is 1 way to have 4 boys:(BBBB)
There is 1 way to have 4 boys and 16 ways to have 4 children:
Happy Calculating!!!
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