SOLUTION: My answer to the problem stated below 1/10 = 0.1 Am I correct? Problem: A couple plans to have 4 children.Assuming the probability of obtaining each sex is 50% (1 in 2), find

Question 54142: My answer to the problem stated below 1/10 = 0.1 Am I correct?
Problem:
A couple plans to have 4 children.Assuming the probability of obtaining each sex is 50% (1 in 2), find the probability of the couple getting 4 boys.
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
There's a couple of ways of doing this:
The multiplication rule:
Multiply the probabilty of having a boy and a boy and a boy and a boy.

You can also raise the probability to the power of 4.

If you aren't to that point in your book, P=(#of ways to have 4 boys)/(# of ways to have children)
There is 1 way to have 0 boys: (GGGG)
There are 4 ways to have 1 boys: (BGGG),(GBGG),(GGBG),(GGGB)
There are 6 ways to have 2 boys: (BBGG),(GBBG),(GGBB),(BGBG),(GBGB),(BGGB)
There are 4 ways to have 3 boys: (BBBG),(BBGB),(BGBB),(GBBB)
There is 1 way to have 4 boys:(BBBB)
There is 1 way to have 4 boys and 16 ways to have 4 children:

Happy Calculating!!!

RELATED QUESTIONS
A couple plans to have four children assuming the boys and girls are equally likely find... (answered by Boreal,Theo)

A couple plans to have 6 children. Assuming that boys and girls are equally likely, what... (answered by ikleyn)

A couple plans to have three children. What is the probability of getting at least one... (answered by venugopalramana)

I need to know if my answer is correct on this one. I constructed a diagram and listed... (answered by stanbon)

I have solved this problem, but I doubt if I did this in the correct manner or even if... (answered by richwmiller)

If a couple plans to have eight children, find the probability that they are all of the... (answered by stanbon)

if a couple plans to have 10 children whats the probability of them having at least 2... (answered by stanbon)

if a couple plans to have 10 children whats the probability of them having at most 3... (answered by Edwin McCravy,solver91311,Alan3354)

I can't seem to wrap my mind around how to round an equation at the end of a problem.... (answered by jim_thompson5910,checkley77,rapaljer)