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In a standard deck of cards there are three face cards (a face card is a jack, a queen, and a king) for each of the four suits. So in a deck of cards there are a total of 12 face cards. There also are four aces, one for each suit. The sum of these cards is 12 plus 4 which is 16. That means that in a well shuffled deck there are 16 total cards that are either a face card or an ace.
The probability of drawing a face card or an ace from the deck on a single draw is calculated by dividing the total number of cards (52) into the total number of desired outcomes.
So in this case, the probability of "winning" is 16 divided by 52. Both of these numbers are divisible by 4, so this fraction (16/52) reduces to 4/13. This means that for this problem the probability of drawing a face card or an ace in a single draw is 4/13 (which can be read as "4 in 13" meaning that typically in many trials of this problem you could expect on average to draw a "winner" 4 times in every 13 trials) or by dividing the it out the probability becomes 0.307692 or 30.7692%.
Hope this helps you to understand the problem.