# SOLUTION: Robil can do 2 jobs in 3 days, and Buray can do 5 jobs in 6 days. Robil works for 3 days and then Buray begins to help. How many days will it take to complete a total of 74 jobs?

Algebra ->  Algebra  -> Permutations -> SOLUTION: Robil can do 2 jobs in 3 days, and Buray can do 5 jobs in 6 days. Robil works for 3 days and then Buray begins to help. How many days will it take to complete a total of 74 jobs?      Log On

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 Question 513832: Robil can do 2 jobs in 3 days, and Buray can do 5 jobs in 6 days. Robil works for 3 days and then Buray begins to help. How many days will it take to complete a total of 74 jobs?Found 2 solutions by nerdybill, stanbon:Answer by nerdybill(6951)   (Show Source): You can put this solution on YOUR website!Robil can do 2 jobs in 3 days, and Buray can do 5 jobs in 6 days. Robil works for 3 days and then Buray begins to help. How many days will it take to complete a total of 74 jobs? Let x = time (days) to perform 74 jobs then x(2/3 + 5/6) = 74 multiply both sides by 6: x(4 + 5) = 444 x(9) = 444 x = 444/9 x = 49.33 days or x = 49 days and 8 hours Answer by stanbon(57250)   (Show Source): You can put this solution on YOUR website!Robil can do 2 jobs in 3 days, and Buray can do 5 jobs in 6 days. Robil works for 3 days and then Buray begins to help. How many days will it take to complete a total of 74 jobs? ---- Robil rate = (2/3) job/day Buray rate = (5/6) job/day -------------------------------- Together rate: 1/x job/day Equation: rate + rate = together rate 2/3 + 5/6 = 1/x (12+15)/18 = 1/x 27/18 = 1/x 3/2 = 1/x Together rate: 3/2 job/day --------------------------------- Robil works for 3 days and then Buray begins to help. How many days will it take to complete a total of 74 jobs? ---- In 3 days Buray finishes 3(5/6) = (5/2) jobs That leaves 71 1/2 jobs to do together ----------------- Equation: x(3/2) = 71 1/2 (3/2)x = 143/2 x = (2/3)(143/2) x = 143/3 = 45 3/4 days ================================ Cheers, Stan H. ============