SOLUTION: there are 10 alphabets a, b, c, d, e, f, g, h, i, j. How many arrangements are there where in 'a' precedes 'b' and 'c' precedes 'd'.
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Question 483548: there are 10 alphabets a, b, c, d, e, f, g, h, i, j. How many arrangements are there where in 'a' precedes 'b' and 'c' precedes 'd'.
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
Assume 'ab' and 'cd' are single letters, total 2+6= 8 letters.
Number of ways = 8! = 40320
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