SOLUTION: A certain class has 6 girls and 5 boys. Four of
these students are to line up in the front of the
room, with two girls on either end and two boys
in between. How many such arran
Algebra.Com
Question 481500: A certain class has 6 girls and 5 boys. Four of
these students are to line up in the front of the
room, with two girls on either end and two boys
in between. How many such arrangements are
possible?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
6C4x4C2=(6x5x4!/2x4!)x(4x3x2!/2x2!)=15x6=90 different arrangements possible..
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