SOLUTION: I hope I got this right..can you tell me, please? What are the number of permutations of the letters of the word MATH? 4, 48, 4! or 4.4.4.4 I chose 48, because 4 x 4 = 16

Algebra ->  Algebra  -> Permutations -> SOLUTION: I hope I got this right..can you tell me, please? What are the number of permutations of the letters of the word MATH? 4, 48, 4! or 4.4.4.4 I chose 48, because 4 x 4 = 16       Log On

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Question 47152: I hope I got this right..can you tell me, please?
What are the number of permutations of the letters of the word MATH?
4, 48, 4! or 4.4.4.4
I chose 48, because 4 x 4 = 16 and 16 x 3 = 48
Thank you !!!

Found 2 solutions by pizza, Earlsdon:
Answer by pizza(14) About Me  (Show Source):
You can put this solution on YOUR website!
The answer here should be 4!, which is, in English, either 4 factorial or 4 shriek, which is 4 x 3 x 2 x 1. The logic behind the answer is as the following.
We are trying to create 4-letter words with 4 different letters, M, A, T and H. Consequently, there are 4 possible letters this 4-letter word can start with. Next, we consider the second letter, since one letter has been taken, there remains only three possibilities. Similarly, only 2 letters remain to choose the third letter, and there is no choice for the fourth letter. So multiplying 4 x 3 x 2 x 1 gives 4!.

Answer by Earlsdon(6291) About Me  (Show Source):
You can put this solution on YOUR website!
You are looking for the number of permutations of 4 things (MATH) taken 4 at-a-time.
nPr+=+%28n%21%29%2F%28n-r%29%21 but in this problem, r = n = 4
4P4+=+%284%21%29%2F%284-4%29%21 (4-4)! = 0! = 1
4P4+=+4%21 = 4*3*2*1 = 24