SOLUTION: In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one.

Question 462383: In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one.
Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one.
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P(defective) = 2/11
P(not defective = 9/11
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Binomial Problem with n = 3.
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P(0<= x <=1) = P(x=0) + P(x=1)
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= (9/11)^3 + 3(2/11)(9/11)^2
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= 0.5477 + 0.3651
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= 0.9128
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Cheers,
Stan H.
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Cheers,
Stan H.
============
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(9C1*2C2)/11C3
=9/165 probability that sample contains 2 defective players.
1 - 9/165 = 156/165 the probability that a sample of 3 CD players will contain no more than one defective one.
.
Ed

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