SOLUTION: how many 3 digit codes can be formed from the set 2, 4, 6, 8, if no digit can be repeated?
Algebra.Com
Question 461183: how many 3 digit codes can be formed from the set 2, 4, 6, 8, if no digit can be repeated?
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
Number of possible codes = 4P3 = 24
RELATED QUESTIONS
pls help... answer ASAP :
a three digit code is made up of three diff. digts from (answered by Theo,richard1234)
How many 4-digit numbers greater than 6000 can be formed with the digits 1, 3, 6 and 8 if (answered by checkley77)
How many four-digit numerical codes can be created if no digit may be repeated?... (answered by psbhowmick)
How many two-digit numbers can be formed from the digits 2, 4, 6, 8, 9 if:
no digit is... (answered by ikleyn)
How many 3 digit all even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if... (answered by ikleyn)
How many numbers of 5 digits can be formed with the digits 0, 1, 2, 3, 4, 6 & 8 with no... (answered by Edwin McCravy)
How many three-digit numbers can be formed using the digits 2,3,5,7,8 if the number is... (answered by ikleyn)
How many two-digit numbers can formed if the first digit cannot be 0 and no digit can be... (answered by stanbon)
Using the digit set (0,1,2,3,4,5) how many 4-digit numbers can be formed if the number... (answered by Edwin McCravy)