SOLUTION: How many 8 digit numbers are there containing three 6s and five 2s?
Algebra.Com
Question 459530: How many 8 digit numbers are there containing three 6s and five 2s?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
This is equivalent to ordering three 6's and five 2's in a line. The number of ways is 8C3 = 8!/(5!3!) = 56.
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