Hi,

Note: as order is not important, these are solved using Combinations:

     nCx = 

A team of 5 is to be chosen from 4 men and 5 women to work on a special project

i. In how many ways can the team be chosen? 9C5 = 126 ways

ii. In how many ways can the team be chosen to include just three women?

              5C3*4C2 = 10*6 = 60 ways

iii. What is the probability that the team includes just 3 women? 60/126

iv. What is the probability that the team includes at least 3 women?

  P(at least 3 women) = 1 - P(0 women ) -P(1 women ) -P(2 women )

                      = 1 - (0  - 5C1*4C4 - 5C2*4C3) / 9C5

v. What is the probability that the team includes more men than women?

   P(more men than women) = P(4men) + p(3men) = (5C1*4C4+ 5C2*4C3)/9C5



 

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