That depends on whether, say, these three table seating arrangements ____________ ____________ ____________ | Tom Ann | | Meg Tom | | Meg Sam | | | | | | | | | | | | | |_Sam___Meg__| |_Ann__Sam___| |_Ann__Tom___| are considered as three DIFFERENT seating arrangements or whether they are considered to all three be the SAME seating arrangement: If the three above are considered to be DIFFERENT seating arrangements, then there are 16 seats to place 16 students, so the answer is 16! = 16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1 = 2.09x10^13 But if those are considered to all be the same seating arrangement (because they can take any of the four seats at the tables) then the answer is (16C4)(12C4)(8C4)(4C4) = (1820)(495)(70)(1) = 63,063,000 Edwin