# SOLUTION: A baseball manager chooses his lineup 1-9. How many ways can he organize his lineup if the pitcher doe not hit in the first four? I did 9*8*7*6*6*5*4*3*2 is this correct?

Algebra ->  Algebra  -> Permutations -> SOLUTION: A baseball manager chooses his lineup 1-9. How many ways can he organize his lineup if the pitcher doe not hit in the first four? I did 9*8*7*6*6*5*4*3*2 is this correct?      Log On

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 Question 397991: A baseball manager chooses his lineup 1-9. How many ways can he organize his lineup if the pitcher doe not hit in the first four? I did 9*8*7*6*6*5*4*3*2 is this correct?Found 2 solutions by josmiceli, stanbon:Answer by josmiceli(9817)   (Show Source): You can put this solution on YOUR website!If the top of the lineup is considered first, there are only 8 choices for 1st batter, then 7 choices, 6, and 5 So the number of choices for the top 4 positions are then the pitcher becomes available plus the 4 others left. , next here are 4 choices, then 3, 2, and 1 is the sum of all the choices Hope I got it right Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!A baseball manager chooses his lineup 1-9. How many ways can he organize his lineup if the pitcher does not hit in the first four? I did 9*8*7*6*6*5*4*3*2 ----- Since the pitcher is not in the 1st four, 8 ways to choose 1st 7 ways to choose 2nd 6 ways to choose 3rd 5 ways to choose 4th 5 ways to choose 3rd 4 ways 3 ways 2 ways 1 ways ============================= Cheers, Stan H.