SOLUTION: Suppose two distinct integers are chosen from between 5 and 17, inclusive. What is the probability that their product is odd?
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Question 393531: Suppose two distinct integers are chosen from between 5 and 17, inclusive. What is the probability that their product is odd?
Found 2 solutions by solver91311, sudhanshu_kmr:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In order for a product to be odd, both factors must be odd. That is because by definition a number with an even factor is even.
There are 13 numbers from 5 to 17 inclusive. 7 of them are odd. There is a 
probability that the first number selected will be odd. Given that the first number selected is odd, there is a 
probability that the next number will be odd given that the second number selected has to be different from the first.
John
My calculator said it, I believe it, that settles it
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
there are 13 integers, 7 are odds and 6 are evens....
product of two integers will be odd if both are odd integers...
no. of ways to choose 2 odd integer out of 7 = 7C2 = 21
no. of ways to choose 2 integers out of 13 integers = 13C2 = 78
probability = 21/78 = 7/26
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