SOLUTION: Please help me solve this problem.
How many distinct arrangements can be made with the letters in the
palindrome “Madam I’m Adam”? (Disregard the apostrophe and
capitaliza
Algebra.Com
Question 389187: Please help me solve this problem.
How many distinct arrangements can be made with the letters in the
palindrome “Madam I’m Adam”? (Disregard the apostrophe and
capitalization.)
Found 2 solutions by stanbon, richard1234:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many distinct arrangements can be made with the letters in the
palindrome “Madam I’m Adam”? (Disregard the apostrophe and
capitalization.)
------------
11!/[4!*4!*2!) = 34650
==========
Cheers,
Stan H.
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
There are 11 factorial ways to arrange the letters, if they are all distinguishable. However, the A's are indistinguishable, so are the M's, etc. To account for the four A's, we divide by 4! since each permutation is being counted 4! times. Do the same with the M's and D's. Thus the total number is
11!/(4!4!2!)
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