Question 379058: is there 362880 distinguishable of the letters in the word TEXTBOOKS? explain. Found 2 solutions by richard1234, stanbon:Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! If all of the letters in TEXTBOOKS were distinct, then there would be 9! = 362,880 ways to arrange the letters. However, there are two O's and two T's. To deal with this over-counting, we divide by 2 to account for the O's (since something like BOTXKOTSE is counted twice) and divide by 2 again for the T's. This leaves us 9!/4, or 90,720 distinguishable ways.
You can put this solution on YOUR website! are there 362880 distinguishable arrangements of the letters in the word TEXTBOOKS? explain.
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# of permutations = 9!/[2!*2!] = 362880/4 = 90720
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Ans. to the question is NO.
Why? Because the TT and the OO are indistinguishable letters so they
do not add to the numbers of distinct arrangements.
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Cheers,
Stan
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