# SOLUTION: Please help me solve this: Jury selection. In how many ways can 12 jurors and 2 alternates be chosen from a group of 20 prospective jurors?

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 Click here to see ALL problems on Permutations Question 360174: Please help me solve this: Jury selection. In how many ways can 12 jurors and 2 alternates be chosen from a group of 20 prospective jurors?Found 2 solutions by Alan3354, sudhanshu_kmr:Answer by Alan3354(30983)   (Show Source): You can put this solution on YOUR website!14 are to be chosen. The 1st is 1 of 20. The 2nd is 1 of 19, etc --> 20*19*18*17*16*15*14*13*12*11*10*9*8*7...1 -------------- But, since a jury of A, B, C, D ... etc is the same as A, D, B, C... it's necessary to divide by 14*13*12*...1 The result is 20*19*18*17*16*15*14*13*12*11*10*9*8*7 This is 20!/((20-14)!*14!) = 20!/14!6! = 38760 possibilities -------------- Answer by sudhanshu_kmr(1152)   (Show Source): You can put this solution on YOUR website! Total no. of jurors = 20 no. of ways to choose 12 jurors from 20 = 20C12 no. of ways to choose 2 alternates from remaining 8 = 8C2 total no. of ways = 20C12 * 8C2 = 3527160 It is possible that some typing mistake in solution of a problem, if any please ignore it. Understand the concept and try to solve the problem yourself. If there is problem related to concept, contact at sudhanshu.cochin@yahoo.com or sudhanshu.cochin@gmail.com Best of luck.......