SOLUTION: Please help me solve this:
Jury selection. In how many ways can 12 jurors and 2 alternates be chosen from a group of 20 prospective jurors?
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Question 360174: Please help me solve this:
Jury selection. In how many ways can 12 jurors and 2 alternates be chosen from a group of 20 prospective jurors?
Found 2 solutions by Alan3354, sudhanshu_kmr:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
14 are to be chosen.
The 1st is 1 of 20.
The 2nd is 1 of 19, etc
--> 20*19*18*17*16*15*14*13*12*11*10*9*8*7...1
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But, since a jury of A, B, C, D ... etc is the same as A, D, B, C... it's necessary to divide by 14*13*12*...1
The result is 20*19*18*17*16*15*14*13*12*11*10*9*8*7
This is 20!/((20-14)!*14!)
= 20!/14!6!
= 38760 possibilities
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Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
Total no. of jurors = 20
no. of ways to choose 12 jurors from 20 = 20C12
no. of ways to choose 2 alternates from remaining 8 = 8C2
total no. of ways = 20C12 * 8C2
= 3527160
It is possible that some typing mistake in solution of a problem, if any please ignore it. Understand the concept and try to solve the problem yourself. If there is problem related to concept, contact at
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Best of luck.......
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