SOLUTION: In how many ways can five math books and four novels be placed on a bookshelf if the math books must be together?

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Question 356905: In how many ways can five math books and four novels be placed on a bookshelf if the math books must be together?
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
| | | | | |N|N|N|N|
|M|M|M|M|M|O|O|O|O|
|A|A|A|A|A|V|V|V|V|
|T|T|T|T|T|E|E|E|E| 
|H|H|H|H|H|L|L|L|L|  

For the above way of placing the books, there are 5! ways to
arranging the math books, and for each of those ways there
are 4! ways of arranging the novels.  That's 5!4! ways for
having all 5 math books on the left and all four novels on
the right.


|N| | | | | |N|N|N|
|O|M|M|M|M|M|O|O|O|
|V|A|A|A|A|A|V|V|V|
|E|T|T|T|T|T|E|E|E|
|L|H|H|H|H|H|L|L|L|

For the above way of placing the books, there are 5! ways to
arranging the math books, and for each of those ways there
are 4! ways of arranging the novels.  That's 5!4! ways for
having 1 novel on the left, then the 5 math books, then 4 
novels on the right.

|N|N| | | | | |N|N|
|O|O|M|M|M|M|M|O|O|
|V|V|A|A|A|A|A|V|V|
|E|E|T|T|T|T|T|E|E|
|L|L|H|H|H|H|H|L|L|

For the above way of placing the books, there are 5! ways to
arranging the math books, and for each of those ways there
are 4! ways of arranging the novels.  That's 5!4! ways for
having 2 novels on the left, then the 5 math books, then 2 
novels on the right.


|N|N|N| | | | | |N|
|O|O|O|M|M|M|M|M|O|
|V|V|V|A|A|A|A|A|V|
|E|E|E|T|T|T|T|T|E|
|L|L|L|H|H|H|H|H|L|

For the above way of placing the books, there are 5! ways to
arranging the math books, and for each of those ways there
are 4! ways of arranging the novels.  That's 5!4! ways for
having 3 novels on the left, then the 5 math books, then 1 
novels on the right.


|N|N|N|N| | | | | |
|O|O|O|O|M|M|M|M|M|
|V|V|V|V|A|A|A|A|A|
|E|E|E|E|T|T|T|T|T|
|L|L|L|L|H|H|H|H|H|

For the above way of placing the books, there are 5! ways to
arranging the math books, and for each of those ways there
are 4! ways of arranging the novels.  That's 5!4! ways for
having all four novels on the left and all five math books on
the right.

That's a total of 5*5!*4! = 14400

Edwin

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