SOLUTION: A committee of six is to be chosen from 9 females and 8 males. What is the probability that a six person committee will have at least 5 females?
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Question 309201: A committee of six is to be chosen from 9 females and 8 males. What is the probability that a six person committee will have at least 5 females?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You need the probability of 
successes in 
trials where 
is the probability of success on any given trial.
\ =\ \left(n\cr k\right\)p^k\left(1\,-\,p\right)^{n\,-\,k})
Where )
is the number of ways to select things from things where order doesn't matter and is computed by !})
For this problem:
\ =\ \left(6\cr 5\right\)\left(\frac{9}{17}\right)^5\left(\frac{8}{17}\right))
I'm going to give you a treat and let you do your own arithmetic.
John
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