SOLUTION: An urn contains 3 white balls and 5 red balls. Two balls are drawn at random. If the first is replaced before the second is drawn, what is the probability that the first ball is

SOLUTION: An urn contains 3 white balls and 5 red balls. Two balls are drawn at random. If the first is replaced before the second is drawn, what is the probability that the first ball is

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Question 257468: An urn contains 3 white balls and 5 red balls. Two balls are drawn at random. If the first is replaced before the second is drawn, what is the probability that the first ball is white and the second is red?
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
P(white then red) = 3/8*5/8 = 15/64.
Since we are replacing, the denominator stays the same.
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