SOLUTION: I am having a dinner party with five fuests. I have 11 friends from which to choose as guests.
From how many different collections of five dinner guests can i choose if two are
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Question 243101: I am having a dinner party with five fuests. I have 11 friends from which to choose as guests.
From how many different collections of five dinner guests can i choose if two are married to eachother and won't come seperatly?
From how many different collections of five dinner guests may she choose if two are divorced from eachother and refuse to come together?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I am having a dinner party with five guests. I have 11 friends from which to choose as guests.
From how many different collections of five dinner guests can i choose if two are married to each other and won't come seperatly?
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Treat those two married persons as one person.
# of groups of 5 will be 10C5 = 1052
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From how many different collections of five dinner guests may she choose if two are divorced from each other and refuse to come together?
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Choose one of those divorced folks: 2 ways
Choose 4 others to join that person: 9C4 = 126 ways
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Total # of groups of 5: 2*126 = 252
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Cheers,
Stan H.
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