SOLUTION: You have five people running for class president. How many different ways can their names be placed on the ballot expressed in algebraic terms?

Question 1988: You have five people running for class president.
How many different ways can their names be placed on the ballot expressed in algebraic terms?
Found 2 solutions by longjonsilver, anish123:
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
first person can be placed in 5 positions.
Once that is done, the second person has 4 positions free.
Third has 3 positions
Fourth has 2
and fifth person has just one position.
so, number of permutations are 5x4x3x2x1 which is called 5!, or 5-factorial

jon
Answer by anish123(1) (Show Source): You can put this solution on YOUR website!
first place in 5 ways
second place in 4 ways
third place in 3 ways
fourth place in 2 ways and the last place in 1 way. the possible number of ways is 5*4*3*2*1=120

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