SOLUTION: how many3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

Question 166200: how many3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

Found 2 solutions by checkley77, edjones:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
9*8*7=504 possible 3 digit numbers without repeats.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
9P3=9!/(9-3)!=9*8*7*6!/6!=504
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