SOLUTION: there are five students, they are A, B, C, D, and E. They are want to sit down on the chair. how many ways the five students can sit if A must beside B?

Question 159546: there are five students, they are A, B, C, D, and E. They are want to sit down on the chair. how many ways the five students can sit if A must beside B?
Found 3 solutions by atique.ah, serena B, Ali-aithzaz:
Answer by atique.ah(27)   (Show Source): You can put this solution on YOUR website!
There are 5 ways A can sit.
There is only 1 way that B can sit.
There are 3ways C can sit.
There are 2 ways that D can sit.
And last there is only 1 way left for E.
The total numbers of ways A B C D E can sit =5*1*3*2*1=30 ways.
Answer by serena B(1)   (Show Source): You can put this solution on YOUR website!
There are 5 students but 2 wants to sit to gether....so we count them as one
so there are 4 now
eg. CDE(AB)<< Ab is counted as one, however AB can sit 2 ways together either (BA) or (AB)
answer would be= 4! * 2!=48
Answer by Ali-aithzaz(4)   (Show Source): You can put this solution on YOUR website!
AB---
-AB--
--AB-
---AB
total 4 ways A comes beside B, and they can change position in 2! Ways total ways 2!*3!*4
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