SOLUTION: How many ways can a baseball coach choose the first, second and third batters in the lineup of a team of 15 players.
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Question 148291: How many ways can a baseball coach choose the first, second and third batters in the lineup of a team of 15 players. Answer by Alan3354(21584) (Show Source):
You can put this solution on YOUR website! For the 1st, he can choose any of 15
For the 2nd, any of the remaining 14
For the 3rd, any of the remaining 13
So for the 1st, there are 15 choices, then 14, then 13.
# of combinations = 15*14*13 = 2,730.
