SOLUTION: How many different numbers can be formed with the digits 2,4,6,8,0 each being divisible by ten, repetition of the digits being not allowed?
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Question 125203: How many different numbers can be formed with the digits 2,4,6,8,0 each being divisible by ten, repetition of the digits being not allowed?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
(4*3*2*1)+(4*3*2)+(4*3)+4=24+24+12+4=64
5 DIGIT NUMBERS +4 DIGIT NUMBERS + 3 DIGIT NUMBERS +2 DIGIT NUMBERS ALL ENDING IN 0.
EXAMPLES:
86240
2640
640
40
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