.
(a) How many different ways can 2 letters from the word SELECT be arranged?
(b) How many different ways can 3 letters from the word SELECT be arranged?
~~~~~~~~~~~~~~~~~~
Part (a)
In the word SELECT, there are 5 different letters S, E, L, C, T,
and one letter, E, is repeated twice.
The word "arranged" means considering distinguishable permutations.
So, consider the word SELCT. It has 5 unique letters (with no repeating).
The number of all possible permutations of its two letters is 5*4 = 20.
All these pairs are distinguishable.
To it, we need to add one pair EE, and then these 21 = 20+1 pairs will
present all possible distinguishable pairs.
ANSWER to (a) : 21 different distinguishable pairs, or 21 different ways.
Part (b)
To solve (b), I will follow the similar logic.
First, the number of all different triples, constituted of 5 different letters without repetitions, is
5*4*3 = 60.
The number of all different triples, constituted of two E and any one of remaining 4 letters is
= = 4*3 = 12.
To get the total number of all distinguishable triples, we should add 60 and 12.
ANSWER to (b)) : 72 different distinguishable triples, or 72 different ways.
Solved.