So, there are 4 blue balls and 5+3 = 8 not-blue balls in the box. We can select 2 blue balls from 4 blue balls in= = 6 different ways. We can select 2 not-blue balls from 8 not-blue balls in = = 28 different ways. Thus we can comprise a quadruple consisting of 2 blue and 2 not-blue balls in = 6*28 = 168 different ways. ANSWER