SOLUTION: You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls. If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing

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Question 1201421: You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls. If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing:
a) All red balls?
b) All green balls?
c) All blue balls?
d) A red ball, a blue ball and a green ball in THAT ORDER?
e) A red ball, a blue ball and a green ball in ANY ORDER?
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
You are going to draw 3 balls from the sack containing, 7 red balls,5 green balls, and 4 blue balls.
If you REPLACE THE BALLS AFTER EACH DRAWING, what is the probability of drawing:
a) All red balls?
b) All green balls?
c) All blue balls?
d) A red ball, a blue ball and a green ball in THAT ORDER?
e) A red ball, a blue ball and a green ball in ANY ORDER?
~~~~~~~~~~~~~~~~~~~~~~~ 


Total balls is 7 + 5 + 4 = 16.


(a)  P =  = .


(b)  P =  = .


(c)  P =  =  = .


(d)  P =  = reduce it.


(e)  P =  = reduce it.  

     Here 6 = 1*2*3 is the number of all possible permutations of 3 items.

I answered all your questions.



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