SOLUTION: If you are going to be drawing 3 balls from a sack containing 4 red balls, 3 green balls and 6 blue balls. If you DO NOT REPLACE the balls after each drawing, what is the probabili

Question 1201418: If you are going to be drawing 3 balls from a sack containing 4 red balls, 3 green balls and 6 blue balls. If you DO NOT REPLACE the balls after each drawing, what is the probability of drawing:
a) all red balls?
b) all green balls?
c) all blue balls?
d) A red ball, a blue ball and a green ball in that order?
e) A red ball, a blue ball and a green ball in any order?
Answer by ikleyn(52767) (Show Source): You can put this solution on YOUR website!
.


Total balls is 4 + 3 + 6 = 13.


(a)  P =  =  =  = reduce this fraction.


(b)  P =  =  = reduce this fraction.


(c)  P =  =  = reduce this fraction.


(d)  P =  = reduce it.


(e)  P =  = reduce it.  

     Here 6 = 1*2*3 is the number of all possible permutations of 3 items.

I answered all your questions.

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